Twice The Sum Of My Digits Is 22 The Product Of My Digits Is 24 My Tens Digit Is Greater Than My Ones Digit What Number Am I

I need help with this question

Solution

Let x=the tens digit let y = the ones digit   2x+2y=22. (Twice the sum of my digits is22   xy=24 (the product of my digits is 24   dividing the first equation by 2 we can find y in terms of x   2x + 2y =22 x+y=11 y=11-x   x(11-x)=24 11x-x^2=24 0=x^2-11x+24   now factotum and solve   0=(x-3)(x-8)   set at each factor to 0   0=x-3. X=3 0=x-8. X=8   since the tens digit is greater. The number is 83