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Write a definite integral that gives the area between y = x^2 and the x-axis over the interval [-1,3]. DO NOT EVALUATE THE INTEGRAL.
Solution
Remember the integral from -1 to 0 will give a negative value.
To get the actual area (not the algebraic area), you need to change the sign of the integral from -1 to 0 and add the integral from 0 to 3.
The integrand of course is x2.