Assume That The Readings At Freezing On A Batch Of Thermometers Are Normall

 A single thermometer is randomly selected and tested. Find P94, the 94-percentile. This is the temperature reading separating the bottom 94% from the top 6%.

P94 = _______°C

Solution

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Use z = (x – μ)/σ or x = zσ + μ

Given: μ = 0 oC, σ = 1.00 oC

94% = .9400 on a z-table falls half-way between z = 1.55 and z = 1.56 –> z = 1.555

x = 1.555(1.00 oC) + 0 oC = 1.555 oC

P94 = 1.555 oC