A 7 00 Ft Tall Man Walks At 6 00 Ft S Toward A Street Light That Is 18 0 Ft

Use the direction in which the distance from the street light increases as the positive direction.

Solution


Get a formula for the shadow’s length in terms of time

The shadow’s length = x in feet

t= time in seconds

7/x = 18/(x+15-6t) ratios of two sides of similar triangles are equal

solve for x in terms of t; cross multiply

11x = 105 – 42t

x = 105/11 -42t/11

take derivative

dx/dt = -42/11 feet per second = – 3 9/11 ft/sec

The shadow is getting shorter by almost 4 feet every second