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Question: Find the derivative of the function f(x)=x3−5×2+6x−2f(x) = x^3 – 5x^2 + 6x – 2.
Solution:
To find the derivative of the function f(x)=x3−5×2+6x−2f(x) = x^3 – 5x^2 + 6x – 2, we will use the power rule of differentiation. The power rule states that if f(x)=xnf(x) = x^n, then f′(x)=nxn−1f'(x) = nx^{n-1}.
Applying the power rule to each term in the function:
- For the term x3x^3: ddx(x3)=3×2\frac{d}{dx}(x^3) = 3x^2
- For the term −5×2-5x^2: ddx(−5×2)=−5⋅2x=−10x\frac{d}{dx}(-5x^2) = -5 \cdot 2x = -10x
- For the term 6x6x: ddx(6x)=6\frac{d}{dx}(6x) = 6
- For the constant term −2-2: ddx(−2)=0\frac{d}{dx}(-2) = 0
Now, combining these results, the derivative of the function f(x)f(x) is: f′(x)=3×2−10x+6f'(x) = 3x^2 – 10x + 6
So, the derivative of f(x)=x3−5×2+6x−2f(x) = x^3 – 5x^2 + 6x – 2 is: f′(x)=3×2−10x+6f'(x) = 3x^2 – 10x + 6