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b/a+b and 0.5
a + 13c and b + 13c, where c is the population of the third state
a – b/2 and a – b/2
a + b and 2b
5(a + b) and (a + b)5
Solution
population of state a > than population of state b
a) b/a+b and 0.5
Since a>b, b/a will be < 1. Thus b/a + b will be a bit more than b > 0.5 (States can’t have fractional populations).
b) a + 13c and b + 13c, where c is the population of the third state
Adding 13c to both sides does not change the relation between a and b, so a+13c > b+13c
c) a – b/2 and a – b/2
These terms are equal to each other.
d) a + b and 2b
It is given that a>b so a+b > b+b = 2b
e) 5(a + b) and (a + b)5
5(a+b) = 5a+5b. (a+b)5 = a*5+b*5, but this equals 5a+5b. The two terms are equal.